Question
A thin metal plate is insulated on the back and exposed to solar radiation on the front surface. The exposed surface of the plate has an absorptivity of 0.8 for solar radiation. If solar radiation is incident on the plate at a rate of $450 \mathrm{W} / \mathrm{m}^{2}$ and the surrounding air temperature is $25^{\circ} \mathrm{C}$, determine the surface temperature of the plate when the heat loss by convection equals the solar energy absorbed by the plate. Assume the convection heat transfer coefficient to be $50 \mathrm{W} / \mathrm{m}^{2} \cdot^{\circ} \mathrm{C}$ and disregard heat loss by radiation.
Step 1
At equilibrium, the heat absorbed by the plate from the solar radiation equals the heat lost by the plate due to convection. Mathematically, this can be expressed as: \[Q_{\text{in}} = Q_{\text{out}}\] Show more…
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