Question
A thin spherical conducting shell of radius $\mathrm{R}$ has a charge q. Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point p a distance $(\mathrm{R} / 2)$ from the centre of the shell is .....(A) $\left[(q+Q) /\left(4 \pi \epsilon_{0}\right)\right](2 / R)$(B) $\left[\left\{(2 Q) /\left(4 \pi \epsilon_{0} R\right)\right\}-\left\{(2 Q) /\left(4 \pi \epsilon_{0} R\right)\right]\right.$(C) $\left[\left\{(2 Q) /\left(4 \pi \in_{0} R\right)\right\}+\left\{q /\left(4 \pi \epsilon_{0} R\right)\right]\right.$(D) $\left[(2 \mathrm{Q}) /\left(4 \pi \epsilon_{0} \mathrm{R}\right)\right]$
Step 1
Step 1: The electric potential at a point due to a point charge is given by the formula $V = \frac{kQ}{r}$, where $k$ is Coulomb's constant, $Q$ is the charge, and $r$ is the distance from the charge to the point. Show more…
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A thin spherical conducting shell of radius $R$ has a charge $q$. Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $P$ at a distance $R / 2$ from the centre of the shell is (A) $\frac{2 Q}{4 \pi \varepsilon_{0} R}$ (B) $\frac{2 Q}{4 \pi \varepsilon_{0} R}-\frac{2 q}{4 \pi \varepsilon_{0} R}$ (C) $\frac{2 Q}{4 \pi \varepsilon_{0} R}+\frac{q}{4 \pi \varepsilon_{0} R}$ (D) $\frac{(q+Q)}{4 \pi \varepsilon_{0}} \frac{2}{R}$
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A charge $q_{1}$ is placed at the centre of a spherical conducting shell of radius $R$. Conducting shell has a total charge $q_{2} .$ Electrostatic potential energy of the system (A) $\frac{q_{1}^{2}+2 q_{1} q_{2}}{8 \pi \varepsilon_{0} R}$ (B) $\frac{q_{2}^{2}+2 q_{1} q_{2}}{8 \pi \varepsilon_{0} R}$ (C) $\frac{q_{1}^{2}+q_{1} q_{2}}{4 \pi \varepsilon_{0} R}$ (D) $\frac{q_{2}^{2}+q_{1} q_{2}}{4 \pi \varepsilon_{0} R}$
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