00:01
Hi there, so for this problem, we have three charges that are situated at the corners of a square of side a, as is shown in this figure.
00:11
Now, the question in this is how much work does take to bring in another charge positive q from far away and place it in the fourth corner in this one right here? so to solve this, we start with the potential that we know is going to be 1 over 4 times pi times epsilon sub 0 times the sum of the charges divided by the position of those charges.
00:49
In this case, we know that there is going to be a charge at a position a negative charge.
01:00
Another charge at a position a as well, and another charge, the one that is in the opposite corner.
01:11
And to obtain that distance, we use the pythagarin theorem, and we will obtain that the length in this is going to be the square root of 2 times a.
01:24
So with that, we can write that the potential is equal to 1 over 4 times pi times epsilon sub 0, minus q divided by a plus q divided by the square root of 2 times a plus minus q divided by a.
01:58
So with this, we can simply simplify this as the charge q divided by 4 times pi times epsilon x0 times a times minus 2 plus 1 over the square root of 2.
02:18
So we know that the word done on the fourth charge is equal to the charge q times the potential.
02:30
So we just, we're going to have that this is just simply the charge q square divided by four times pi times epsilon sub zero times a.
02:41
And this times minus 2 plus 1 over the square root of 2.
02:49
So that's a solution for part a of this problem.
02:55
Now for part b, we are asked about how much work does it take to assemble the whole configuration of four charges? so we start with the work that we have done to put the first charge, charge 1.
03:15
We know that in this case, there is no other charges present at that moment...