Question
A tornado rips off a $100-\mathrm{m}^{2}$ roof with a mass of $1000 \mathrm{~kg}$. What is the minimum vacuum pressure needed to do that if we neglect the anchoring forces?
Step 1
First, we need to find the weight of the roof, which is the force due to gravity acting on it. We can use the formula: Weight (W) = mass (m) × acceleration due to gravity (g) where g is approximately 9.8 m/s². Show more…
Show all steps
Your feedback will help us improve your experience
Sophie S and 53 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A tornado rips off a $1000-\mathrm{ft}^{2}$ roof with a mass of $2000 \mathrm{lbm}$. What is the minimum vacuum pressure needed to do that if we neglect the anchoring forces?
within the funnel of a tornado the air pressure is much lower than normal about 200 mbar as compared to the normal value of 1010 mbar. suppose that such a tornado suddenly envelops a house; the air pressure inside the house is 1010 mbar and the pressure outside suddenly drops to 200 mbar. This will cause the house to burst explosively. what is the net outward pressure force on a 12 m x 3 m wall of this house? is the house likely to suffer less damage if all the windows and doors are open?
In a tornado or hurricane, a roof may tear away from the house because of a difference in pressure between the air inside and the air outside. Suppose that air is blowing across the top of a $2000 \mathrm{ft}^{2}$ roof at $150 \mathrm{mi} / \mathrm{h}$. What is the magnitude of the force on the roof?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD