A toroid has a major radius $R$ and a minor radius $r,$ and is tightly wound with $N$ turns of wire, as shown in Figure P32.12. If $R>>r,$ the magnetic field in the region enclosed by the wire of the torus, of cross-sectional area $A=\pi r^{2},$ is essentially the same as the magnetic field of a solenoid that has been bent into a large circle of radius $R$ . Modeling the field as the uniform field of a long solenoid, show that the self-inductance of such a toroid is approximately
$$
L \approx \frac{\mu_{0} N^{2} A}{2 \pi R}
$$
(An exact expression of the inductance of a toroid with a rectangular cross section is derived in Problem $64 . )$