00:07
In problem 4 .83, we have a rod bent into the shape of a circle, held in place with two pegs at point d and e, and there's applied force at b down.
00:20
And since it is a three -force rigid body, all three forces must be concurrent, which means that the lines of action of all three forces must intersect.
00:36
Now since force e and d are at frictionless pegs, it means that their force is going to be normal to the surface they're at.
00:48
And since it is a circle, their force is going to point towards the middle of the circle, which means that all three forces intersect at the middle, the exact middle of the circle.
01:20
And knowing that, we can make some triangles to figure, out what the length of c is.
01:28
We know that a given in the problem is 0 .02 meters, and they're asking us to find the length of c between points e and b.
01:49
So if i draw out the problem as a bunch of triangles it looks like this.
02:15
Points c, d, e, and b.
02:30
I'm going to make a couple other triangles that'll be helpful.
02:36
I'll call this point a to make a right triangle between c e and a.
02:42
And then we also know that this right triangle has the sides of a.
02:51
0 .02 meters.
03:03
Now since these two sides of the right triangle are the same, means that these angles must be 45 degrees.
03:13
We can find the distance d .e.
03:16
By using the pythagorean theorem...