Question
A toy helicopter is flying in a straight line at a constant speed of $4.5 \mathrm{m} / \mathrm{s}$. If a projectile is launched vertically with an initial speed of $v_{0}=28 \mathrm{m} / \mathrm{s}$, what horizontal distance $d$ should the helicopter be from the launch site $S$ if the projectile is to be traveling downward when it strikes the helicopter? Assume that the projectile travels only in the vertical direction.
Step 1
This can be done using the formula $t_1 = \frac{v_0}{g}$, where $v_0$ is the initial speed of the projectile and $g$ is the acceleration due to gravity. Substituting the given values, we get $t_1 = \frac{28}{9.81} = 2.854$ seconds. Show more…
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