A train 200 m long passes over a bridge 600 m long. The time taken by the train to cross the b

Name: Problem 39, Chapter 2: IIT JEE Super Course in Physics: Mechanics I
Uploaded: 2021-06-07T18:06:08-08:00
Duration: 1 min 34 s
Channel: Satpal Satpal
Description: A train 200 m long passes over a bridge 600 m long. The time taken by the train to cross the bridge when the train moves with a uniform speed of 10 m s^-1 is (a) 100 s (b) 40 s (c) 80 s (d) 60 s

step 1 As we know that the total distance traveled in this case is total distance traveled by train in

Question

A train $200 \mathrm{~m}$ long passes over a bridge $600 \mathrm{~m}$ long. The time taken by the train to cross the bridge when the train moves with a uniform speed of $10 \mathrm{~m} \mathrm{~s}^{-1}$ is (a) $100 \mathrm{~s}$ (b) $40 \mathrm{~s}$ (c) $80 \mathrm{~s}$ (d) $60 \mathrm{~s}$

   A train $200 \mathrm{~m}$ long passes over a bridge $600 \mathrm{~m}$ long. The time taken by the train to cross the bridge when the train moves with a uniform speed of $10 \mathrm{~m} \mathrm{~s}^{-1}$ is
(a) $100 \mathrm{~s}$
(b) $40 \mathrm{~s}$
(c) $80 \mathrm{~s}$
(d) $60 \mathrm{~s}$

IIT JEE Super Course in Physics: Mechanics I

Trishna Knowledge… 1st Edition

Chapter 2, Problem 39

Instant Answer

Solved by Expert Satpal Satpal

06/07/2021

Step 1

This is the sum of the length of the train and the length of the bridge. In mathematical terms, this can be written as: \[X = L_{\text{train}} + L_{\text{bridge}}\] where $X$ is the total distance, $L_{\text{train}}$ is the length of the train, and Show more…

Show all steps

Thanks for your feedback!

A train $200 \mathrm{~m}$ long passes over a bridge $600 \mathrm{~m}$ long. The time taken by the train to cross the bridge when the train moves with a uniform speed of $10 \mathrm{~m} \mathrm{~s}^{-1}$ is (a) $100 \mathrm{~s}$ (b) $40 \mathrm{~s}$ (c) $80 \mathrm{~s}$ (d) $60 \mathrm{~s}$

Play audio

Feedback

Satpal Satpal and 89 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Time-Distance Calculation

This involves using the formula time = distance/speed to determine how long an object takes to traverse a given distance. It is a fundamental concept in solving motion problems where speed remains constant.

Relative Distance

In problems involving objects passing stationary obstacles, the total distance covered is the sum of the lengths of the moving object and the obstacle. This concept is crucial in determining how far an object must travel for its entire length to clear an impediment.

Uniform Motion

Uniform motion refers to motion at a constant speed, where the relation between distance, speed, and time is linear. This principle is used to calculate one of these quantities when the other two are known.

Please give Ace some feedback