A train 280 m long is moving at a speed of 60 km / hr. The time taken by the train to cross a

Name: Problem 31, Chapter 15: The Pearson Guide to Objective Arithmetic for Competitive Examinations
Uploaded: 2022-01-08T15:31:36-08:00
Duration: 2 min 29 s
Channel: Vishal Gupta
Description: A train 280 m long is moving at a speed of 60 km / hr. The time taken by the train to cross a platform 220 m long is (a) 30 sec. (b) 40 sec. (c) 60 sec. (d) 20 sec.

step 1 Hi, here in this given problem, length of the train that is given as let it be represented by L1

Question

A train $280 \mathrm{~m}$ long is moving at a speed of $60 \mathrm{~km} /$ $\mathrm{hr}$. The time taken by the train to cross a platform $220 \mathrm{~m}$ long is (a) $30 \mathrm{sec}$. (b) $40 \mathrm{sec}$. (c) $60 \mathrm{sec}$. (d) $20 \mathrm{sec}$.

   A train $280 \mathrm{~m}$ long is moving at a speed of $60 \mathrm{~km} /$ $\mathrm{hr}$. The time taken by the train to cross a platform $220 \mathrm{~m}$ long is
(a) $30 \mathrm{sec}$.
(b) $40 \mathrm{sec}$.
(c) $60 \mathrm{sec}$.
(d) $20 \mathrm{sec}$.

The Pearson Guide to Objective Arithmetic for Competitive Examinations

Dinesh Khattar 2nd Edition

Chapter 15, Problem 31

Instant Answer

Solved by Expert Vishal Gupta

01/08/2022

Step 1

To do this, we use the conversion factor $1 \text{ km/hr} = \frac{1000 \text{ m}}{3600 \text{ s}} = \frac{1}{3.6} \text{ m/s}$. Thus, \[ 60 \text{ km/hr} = 60 \times \frac{1000}{3600} = \frac{60000}{3600} = 16.67 \text{ m/s} \] Show more…

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A train $280 \mathrm{~m}$ long is moving at a speed of $60 \mathrm{~km} /$ $\mathrm{hr}$. The time taken by the train to cross a platform $220 \mathrm{~m}$ long is (a) $30 \mathrm{sec}$. (b) $40 \mathrm{sec}$. (c) $60 \mathrm{sec}$. (d) $20 \mathrm{sec}$.

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Key Concepts

Relative Distance

Relative distance is the total distance that needs to be covered during the motion, which, in problems involving objects passing each other, typically includes the lengths of both objects. This concept is crucial for accurately determining how much distance is involved in the interaction.

Time-Speed-Distance Relationship

The time-speed-distance relationship is a fundamental principle in kinematics, where time is calculated by dividing the total distance by the speed. Understanding this relationship allows one to solve a wide range of problems involving motion by relating these three quantities.

Unit Conversion

Unit conversion is essential when solving physics problems because it ensures that all measurements are in compatible units. For example, converting speed from kilometers per hour to meters per second is often necessary for consistency when calculating distances in meters and times in seconds.

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