A train covers a distance in 50 minutes if it runs at a speed of 48 km / hr. The speed at which

Name: Problem 9, Chapter 15: The Pearson Guide to Objective Arithmetic for Competitive Examinations
Uploaded: 2022-03-06T15:31:49-08:00
Duration: 1 min 56 s
Channel: Saman Zulfiqar
Description: A train covers a distance in 50 minutes if it runs at a speed of 48 km / hr. The speed at which the train must run to reduce the time of joumey to 40 minutes, will be (a) 70 km / hr (b) 80 km / hr (c) 60 km / hr (d) None of these

step 1 Our question is a train has speed of 60 km per hour for the first one hour and 40 km per hour to

Question

A train covers a distance in 50 minutes if it runs at a speed of $48 \mathrm{~km} / \mathrm{hr}$. The speed at which the train must run to reduce the time of joumey to 40 minutes, will be (a) $70 \mathrm{~km} / \mathrm{hr}$ (b) $80 \mathrm{~km} / \mathrm{hr}$ (c) $60 \mathrm{~km} / \mathrm{hr}$ (d) None of these

   A train covers a distance in 50 minutes if it runs at a speed of $48 \mathrm{~km} / \mathrm{hr}$. The speed at which the train must run to reduce the time of joumey to 40 minutes, will be 
(a) $70 \mathrm{~km} / \mathrm{hr}$
(b) $80 \mathrm{~km} / \mathrm{hr}$
(c) $60 \mathrm{~km} / \mathrm{hr}$
(d) None of these

The Pearson Guide to Objective Arithmetic for Competitive Examinations

Dinesh Khattar 2nd Edition

Chapter 15, Problem 9

Instant Answer

Solved by Expert Saman Zulfiqar

03/06/2022

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Step 1: First, we need to calculate the distance covered by the train in 50 minutes at a speed of 48 km/hr. Show more…

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A train covers a distance in 50 minutes if it runs at a speed of $48 \mathrm{~km} / \mathrm{hr}$. The speed at which the train must run to reduce the time of joumey to 40 minutes, will be (a) $70 \mathrm{~km} / \mathrm{hr}$ (b) $80 \mathrm{~km} / \mathrm{hr}$ (c) $60 \mathrm{~km} / \mathrm{hr}$ (d) None of these

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Key Concepts

Unit Conversion

Since time and speed are often expressed in different units (e.g., minutes for time and km/hr for speed), it is essential to convert these units appropriately to maintain consistency when using the speed-time-distance relationship. This ensures that calculations are accurate and the units properly cancel out.

Speed-Time-Distance Relationship

This fundamental principle of kinematics states that the distance traveled by an object is equal to the product of its constant speed and the time it has been in motion. It provides the basis for solving problems where any two of these variables (speed, time, distance) are known, and the third must be determined.

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