00:01
Hi, here in this given problem, length of the train that is given as 92 meter, its initial velocity v i that is 0 and suppose constant velocity of the car that is v c and constant acceleration of the train that is supposed to be a.
00:53
So, in the first case in time t which is equal to 14 second, distance moved by the train that will be given by s is equal to using second equation of motion s equals to v i t plus half a t square means this is s is equal to 0 plus half a which is missing acceleration of the train multiplied by square of 14.
01:37
So, this distance travelled by the train s t comes out to be equal to 98 a and speed gained by the train after in the end of 14 second that will be given by first equation of motion v f is equal to v i plus a t means 0 plus a multiplied by 14 means this is 14 a meter per second and that was meter.
02:10
So, the distance moved by the car in the same time interval as the car is covering the length of the train.
02:26
So, the distance moved by the car s c that will be equal to distance moved by the train plus length of the train.
02:47
So, the constant speed of the car v c here we assume it to be equal to v c.
02:57
So, v c will be given by speed equals to distance upon time 98 a plus 92 divided by 14...