00:01
So for this problem, i already kind of do the basics.
00:04
We'll be doing three graphs here.
00:06
And to start off with part a, this is a graph at t equals zero.
00:16
And so to label this graph, it starts at negative 10, goes to negative 5, 0, 5, and 10.
00:26
Then it starts at 0, 0 .5, 1 .0, 1 .5, and 2 .0.
00:35
So at t equals zero seconds, it is at zero.
00:42
So we know that the graph is going to go like this.
00:52
That is a graph for t equals zero.
00:56
So for part b, the wave function is found by replacing x in the pulse by x minus vt.
01:06
So we have d of x of t is equivalent to 4 .0 meters cubed divided by x minus 2 .4 meters per second times t squared plus 2 .0.
01:35
And that would be your answer for part b...