00:01
So this question gives us the amplitude of two identical waves, which i'm going to call a, which is equal to 5 centimetres.
00:07
And it tells us that they interfere with a given phase difference between the two waves, being the only difference between them.
00:14
And it tells us that the superposition wave has an amplitude of 6 .69 centimeters, which i've called a subscript r for the resultant wave.
00:23
And it asks us to work out the phase difference, phi, between the two waves.
00:30
So we will start by just writing out the expressions generally for the two waves.
00:37
So we have y1 is equal to where we have a sine kx plus omega t.
00:49
And then y2 is identical to y1 just with a phase difference phi.
00:57
So it'll be a sign kx plus omega t plus phi.
01:03
So working out the equation for the resultant wave, we have y is equal to y1 plus y2, and that's going to be equal to, well, there's a common factor of a, which we will pull out, and then we have to add those sign terms, so it'll be sine kx plus omega -t, plus sine kx plus omega -t plus phi.
01:33
So in order to simplify this expression a little bit, we need to use a trigonometric identity, which you can find in the question.
01:43
And we know that sine alpha plus sine beta, and these are just general inputs for sign, is equal to two cosine, and then alpha minus beta over two, multiplied by sine alpha, alpha plus beta, over 2.
02:09
So what we're going to do is we're going to call kx plus omega t alpha and kx plus omega t plus phi as beta.
02:20
So what that allows us to do then is input those alpha and beta values into that expression for sine alpha plus sine beta and that will give us a more simplified expression from which we can use it to work out what phi would be...