A triangle is isosceles if it has two sides of equal length. Suppose that an isosceles triangle has two sides of length $a$ and that the third side is the base, of length $b$. It is a fact that the altitude of such a triangle cuts the base in half. Show that the area of the triangle is given by
$$
\frac{b}{2} \sqrt{a^2-\frac{b^2}{4}} .
$$