00:01
Okay, so for this question, you want us to determine the electrical force externally on the object at the top corner due to the two objects on the bottom.
00:11
So you want us to look in for the, find out the force on the top.
00:15
We know since each object here has charged with 2 .0 cullons and the same distance away from each other, which means that this is a triangle with the same size.
00:27
So the angle should be 60 degrees.
00:30
And you should be 60 degrees on top here in a green mark as well.
00:35
So the red arrow here is the electrical force from each bottom object to the top.
00:42
And if we decompose it to x and y component, we'll find out the x component will cancel out.
00:47
Because it will be in the equal magnitude by opposite direction.
00:52
But on the y axis, the y component forces will add it up.
00:57
So we'll get such equation here which is f -tile is f -1, sine 60 degree, plus f2 sine 60 degree, which is k -q -square over r -square times sine 60 degree plus k -quare over r -square times sine -16 degree.
01:12
Then we'll get 2 k -k -square over r -square times -sq -square over r -square...