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Problem 37 Easy Difficulty

A triangular glass prism with apex angle $\Phi=60.0^{\circ}$ has an index of refraction $n=1.50$ (Fig, P35.37). What is the smallest angle of incidence $\theta_{1}$ for which a light ray can emerge from the other side?

Answer

$\theta_{1}=\left[27.9^{0}\right]$

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Elyse G.

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Video Transcript

since. So what we're trying to do over here is try to find the angles as they emerge on the other direction. So that will be the final way that is getting out. This is the surface normal on inside the surface. It would be passing in that direction on their draw, the surface normal again on then you have the ray coming in in this direction and we have to find what is this angle? The other one. So let's have this angle to be Alfa on this angle to be better. This angle the apex is 60 degree. So this angle over here is 1 20 degree. So we have as of us better. It was 100 and 80 degree. So we have Alfa. It was 180 degrees minus better and no al supplies better is 60 degrees because that constrict the triangle 60 degrees minus. Better on what is better? Better is the critical angle Sign in verse one over the effective index off the glass. And yeah, now that we have Alfa, we confined Tetteh Juan using scientist a one it was and science as far so theta one equals sine inverse and sign Alfa, which is this? Six degrees minus sign in divorce. One over n putting that effective index value using. And it was 1.5 We find Tetteh Juan. It was 27.9 degrees.

Indian Institute of Technology Kharagpur
Top Physics 103 Educators
Elyse G.

Cornell University

Andy C.

University of Michigan - Ann Arbor

Zachary M.

Hope College

Jared E.

University of Winnipeg