A trolley is under the action of a constant force $F$. The sand contained by it is poured out through a hole in the floor at the rate of $m$ per second. If initial mass of sand and trolley was $M$ and initial speed was $u$, then acceleration of trolley is given by
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(a) $\frac{F}{M-m t}$
(b) $\frac{F}{M+m t}$
(c) $\frac{F}{M-m}$
(d) $\frac{F}{M+m}$