00:01
Hi, here in this given problem first of all we show this crate and then the directions north, south and east and west.
00:16
Two forces acting on it, one of the force that is due west, the force is a.
00:27
This force is having a magnitude of 445 newton acting due west.
00:35
Another force acting on the crate force b having a magnitude 325 newton and acting due north.
00:52
In the first part of the problem we have to find direction and magnitude of the resultant force.
00:59
So, if we replace these forces here, this is the force b, this is the force a and we apply parallelogram law of vector addition.
01:12
This will be the net force making an angle theta due north of west.
01:21
So, first of all this resultant will be given by using triangle law of vector addition r is equal to square root of square of magnitude of a plus square of magnitude of b means this is square of 445 plus square of 325 and it is calculated to be equal to 551 .0 newton.
01:51
One of the answer for this first part of the problem.
01:56
Then for the direction tan theta that will be that will be equal to the ratio of the magnitude of b to the magnitude of a, this a.
02:08
So, this is 325 divided by 445 means 0 .730...