00:01
Hi there, so for this problem, we are told that a start that is too heavy to stabilize as a white dwarf can collapse further to form a neutron star.
00:10
That is a start made internally of neutrons supported against gravitational collapse by degenerate neutrons pressure.
00:19
So we need to repeat the steps of the previous problem for the neutron star to determine the following.
00:25
The mass radius relation.
00:28
The radius, density, firm it, energy, and fermin temperature of a one solar mass neutron star and the critical mass above which a neutron star becomes relativistic and hence unstable to further collapse.
00:46
So in a neutron star, the kinetic energy comes from the neutrons, and the number of this is simply the mass of the entire star divided by the number the mass of neutrons in that star, where m, of course, is the total mass, and mn is the mass of a neutron.
01:11
So we can write the kinetic energy as to follow.
01:15
The kinetic energy, in this case, then is equal to 3 over 5 times n, the number n of neutrons, times the fermi energy.
01:30
And now we can write this as 3 over 5, and we write the expression for the fermi energy that we know is plans constant to the square divided by n 8 times the mass of a neutron and this times three times the number and divided by pi times the volume and this elevated to 2 over 3 now we can simplify this expression as follows we can simplify this as 3 times plumps constant to the square divided by 40 times the mass of a neutron, and this times the mass of the star, the total mass, divided by the mass of a neutron, that elevated to 5 over 3, and this times 9, divided by 4 times pi to the square times the radius of the star to the 3, and this elevated to 3 to 2 over 3.
02:30
So that's the expression that we have in here for the kinetic energy.
02:41
Now, so adding the negative gravitational potential energy, we have for the total energy.
02:52
So the total energy is equal to the potential energy plus the kinetic energy.
02:57
So in here we will find that this is minus.
03:02
And we're going to call this alpha divided by the radius, plus beta divided by the radius square, where we are going to define what is gamma and what is beta.
03:15
So alpha, sorry, alpha is equal to 3 over 5 times the gravitational constant g times the mass of the star is square.
03:26
Meanwhile, beta, and from the previous expression, we can deduce that this is equal to 0 .028 times the, plums constant to the square times the mass of the star elevated to 5 over 3, and these divided by the mass of a neutron elevated to 8 over 3.
03:50
So as with a white dwarf star, the equilibrium radius is the one that minimizes the total energy.
04:00
So we're going to set the derivative of the total energy with respect to the radius is equal to 0, and we are going to solve for the radius to find the maximum.
04:12
So it's quite easy to obtain from there that when we derive by this expression and we set that equal to zero, we obtained that the radius is equal to 2 times beta divided by alpha.
04:26
So if we put all of this expression in here, we will have that this is 0 .093, and this times 0 .093.
04:36
Three, and these times plums constant to the square divided by the gravitational constant times the mass of an electron elevated to 8 over 3 times the mass of the start elevated to 1 over 3.
04:53
And here again, the equilibrium radius increases with increasing mass due to the greater gravitational attraction.
05:02
For a one solar mass neutron, this model predicts the following motor produced.
05:07
So we just simply substitute the mass of the sun.
05:15
So we will have.
05:16
In the denominator we have the gravitational constant that we know is 6 .67 times 10 to the minus 11, newton's time meters squared divided by kilograms square...