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This is the answer to chapter 14, problem number 71 from the zoomdahl chemistry textbook.
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This problem asks us to calculate the ph of a solution prepared by dissolving two aspirin tablets and enough water to make 237 milliliters of solution.
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The typical tablet contains 325 milligrams of aspirin, and we're told that the k -a of aspirin is 3 .3 times 10 to the negative fourth.
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So we're also given the formula for aspirin, which is c9h804.
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And from that, we can calculate the molar mass, which we'll need.
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And so i've done that at the top of the screen here, as well as doing the unit conversions.
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Since we're going to be dealing with molarities and molecular masses, we need things in grams, not milligrams, and in liters, not milliliters.
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So those calculations are across the top of the screen.
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Well, not the calculations, but the results of those calculations.
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Okay, so the first thing that we need to do is we need to express the amount of aspirin that we have as a concentration.
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And so in order to do that, so we have 650 milligrams or 0 .650 grams of aspirin.
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And we will use aspirin's molecular mass.
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So one mole of aspirin is going to weigh 180 .158 grams.
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And so we have 0 .03608 moles of aspirin.
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And we can divide that by 0 .237 liters, since that is going to going to be the volume of our solution.
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And that is going to give us a molar figure.
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So for concentration.
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So we end up with 0 .0152 molar.
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And of course, you could express that with scientific notation.
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I'm just going to leave it like this for right now because we have more math to do...