Question
A typical galvanometer, which requires a current of $1.50 \mathrm{~mA}$ for full-scale deflection and has a resistance of $75.0 \Omega$, can be used to measure currents of much greater values. A relatively small shunt resistor is wired in parallel with the galvanometer (refer to Fig. $28.24 \mathrm{a}$ ) so that an operator can measure large currents without causing damage to the galvanometer. Most of the current then flows through the shunt resistor. Calculate the value of the shunt resistor that enables the galvanometer to be used to measure a current of $1.00 \mathrm{~A}$ at fullscale deflection. (Hint: Use Kirchhoff's rules.)
Step 1
50$ milliampere, the resistance of the galvanometer coil, $R_G$, is $75.0$ ohm, and the range of the resultant ammeter, $I$, is $1.00$ ampere. Show more…
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A typical galvanometer, which requires a current of $1.50 \mathrm{mA}$ for full-scale deflection and has a resistance of $75.0 \Omega,$ may be used to measure currents of much greater values. To enable an operator to measure large currents without damage to the galvanometer, a relatively small shunt resistor is wired in parallel with the galvanometer, as suggested in Figure $28.27 .$ Most of the current then goes through the shunt resistor. Calculate the value of the shunt resistor that allows the galvanometer to be used to measure a current of $1.00 \mathrm{A}$ at full-scale deflection. (Suggestion: use Kirchhoff's rules.)
A particular galvanometer serves as a $2.00-\mathrm{V}$ full-scale voltmeter when a $2500-\Omega$ resistor is connected in series with it. It serves as a $0.500-\mathrm{A}$ full-scale ammeter when a $0.220-\Omega$ resistor is connected in parallel with it. Determine the internal resistance of the galvanometer and the current required to produce full-scale deflection.
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