00:01
In this problem, we're given a disk of radius r0 and mass m0, and its moment of inertia is, of course, what we're already given for a disk.
00:13
One half m0, r0 squared, and we're asked to cut out a disk from the center of radius r1 in order to cut its moment of inertia in half.
00:30
So we're going to see right away that the final moment of inertia.
00:37
I'm going to call that i2 is equal to its initial minus the moment of inertia of this disk we're cutting out.
00:49
And that will be equal to i not over 2.
00:57
And so what we can do is add i1 to this.
01:04
Side subtract i not over two from this side and we'll get at the end i not over two is equal to i1 which of course makes sense if we cut out this much and then it has half the moment of inertia then the part we cut out must have the other half of the moment of inertia and so if we break this down we will see that m not are not squared over 4 this over 2 is going to be equal to the moment of inertia of this disk, which we know the moment of inertia of a disk is m1 r1 squared over 2.
01:59
So now we just need to find m1.
02:04
And luckily we have m0 so we can figure out the density of this disk...