00:01
So here they're trying to find the resultant acceleration after it has, after the uniform solid disk has turned through 0 .1 revolutions.
00:10
So we can first write down our givens.
00:16
We have a radius of this uniform solid disk, 0 .4 .00 meters.
00:22
You have a mass of 30 kilograms.
00:30
We also have a theta t of 1 .10 radiance per second and this will be times time.
00:46
This will be plus 6 .3 .0 radiance per second squared times t squared.
00:55
Let's first try to find the angular acceleration is simply derivative of the angular displacement.
01:05
So this will be 1 .10 radiance per second plus 12 .60 radiance per second squared times t.
01:20
And then we can say that the alpha t will simply be the derivative of the angular velocity.
01:28
And this will be 12 .60 radiance per second squared.
01:35
So at this point, we can say that the change in theta is 0 .100 revolutions.
01:48
We also know that there's 2 pi radians per one revolution.
01:53
So this is going to be 0 .628 radians.
02:03
And at this point, we can find the tangential acceleration...