Question
A uniform rod $A B$ of mass $m$ and length $l$ is at rest on a smooth horizontal surface. An impulse $p$ is applied to the end $B$. The time taken by the rod to turn through a right angle is :(a) $2 \pi \frac{m l}{p}$(b) $2 \pi \frac{p}{m l}$(i) $\frac{\pi m l}{12 p}$(d) $\frac{\pi p}{m !}$
Step 1
The initial angular momentum is zero (since the rod is at rest), and the final angular momentum is $I\omega$, where $I$ is the moment of inertia of the rod and $\omega$ is the angular velocity. Therefore, we have \[p = I\omega.\] Show more…
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Kinetics of Rigid Bodies in Three Dimensions
Energy and Momentum of a Rigid Body
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