00:01
In this problem, we need to find the distance b through which the rod will move when it rotates as a result of being struck by the hammer.
00:11
So i have here a sketch of the problem.
00:14
So the rod, which is initially at rest, was struck by a hammer which produces an impulse perpendicular to the rod.
00:24
So at point a and causes the rod to rotate about point a.
00:30
With angular velocity omega and move with a velocity v.
00:40
Now, so let's write an equation for the moments about point a, so taking the counterclockwise direction as positive.
00:52
So our equation would be, so 0 plus 0 equals, so i omega plus, the mass of the rod times the velocity v then times l over 2 because the center of the rod is at a distance l over 2 away from point a.
01:17
So since the body is a rod, so its moment of inertia is given by, so i equals 1 over 12 times the mass of the rod times the square.
01:31
Of its length.
01:34
So solving for v and replacing the moment of inertia with this equation, so our equation becomes, so v equals 2i omega over ml...