00:01
Okay, so this is the equation for the electric view on the axis of the disk, which is equal to 2 pi times ke times sigma, and then times 1 minus x over r squared plus x squared to the power 1 half.
00:12
Ke is the kulon's constant, which is 8 .99 102 .9 newton times meter times meter per koolan square, and sigma is the charge density, which is 7 .90 times 102 power negative 3 koolan per meter.
00:23
And r is the radius, which is 35 centimeter, and we convert the meter is 0 .35 meter.
00:29
And x is the distance to the center of the disk and for question a is given as 5 .0 centimeter which is 0 .05 meter so therefore we can plug in all these values back into the equation to determine the electric view which will give us e is equal to 2 pi times 8 .99 times 10 to the power of 9 newton times meter square per kolon square and then times sigma, which is 7 .90 times 10 to the power of negative 3 colon per meter square.
01:05
And then times 1 minus x, which is 0 .05 meter, and then over r square, which is 0 .35 meter and then square, plus 0 .05 meter and then square, and then to the power of 1 half.
01:36
And this will give us the electric fuel as about 3 .83 times 10 to the power 8 newton per coolant, which is 383 times 10 .5 .6 newton per coolant...