00:01
Okay, so we know the electric fuel is equal to kk over r square.
00:04
K is k is k is k, k is a constant.
00:05
Q is the charge and the r is the distance.
00:08
We know kowloon constant is equal 9 times 10 to power 9 newton times meter square for kulang square.
00:13
And the distance is given as 0 .5a times 10 to the power of negative 12 meter, which is the radius of the nuclear.
00:22
And the charge on nuclear is 92e, since there are 92 protons there, which will give us the total charge on the nuclear system about 1 .472 times 10 to the power of negative 17 kulams.
00:36
So therefore, we can determine the electric field, which is equal to 9 times 10 to the power of 9, newton times medium square for koulon square, and n times 1 .472 times 10 to the power of negative 17 koulon, over 0 .58 times, oh, sorry, 10 to the power of a negative, negative 12 meter, and then to the power of 2.
01:20
And this will give us the electric fuse about 3 .938 times 10 to the power of 17 newton per cool.
01:41
And for question b was asking us the force that was exerted by the electron.
01:47
When a force can be equal to the charge of electron times the electrophue, which is negative e, since the electron has a negative charge.
01:54
So therefore we have force is equal to negative 1 .6 times 10 to the power of negative 19 cologne, and then times the electrophil, which is 3 .938 times 10 to the power of 17, newton per cologne.
02:14
And this will give us the electric force is about negative 0 .063 newton...