Refer a friend and earn $50 when they subscribe to an annual planRefer Now

Get the answer to your homework problem.

Try Numerade Free for 30 Days

Like

Report

(a) Use a ray diagram to determine the approximate location of the image produced by a concave lens when the object is at a distance $\frac{1}{2}|f|$ from the lens. (b) Is the image upright or inverted? (c) Isthe image real or virtual? Explain.

(a) see explanation(b) see explanation(c) see explanation

Physics 103

Chapter 26

Geometrical Optics

Wave Optics

Cornell University

Simon Fraser University

Hope College

Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

(a) Use a ray diagram to d…

03:03

An object is a distance $f…

02:06

An object is a distance 2$…

04:03

Draw a ray diagram to loca…

02:33

(II) (a) Where should an o…

02:05

02:13

An object is located midwa…

20:13

A concave spherical mirror…

03:53

A real object’s distance f…

02:44

An object is located three…

to solve this problem, we first need to create a ray diagram. And as you can see, we have some of those components here already. So the curved line is the con cave near the line. Passing through it is the principal access. The point labeled F is the focal point, or the point from which there is diverge and the point labelled C is the center of curvature. If you imagine that conclave mere going into a complete circle, that point labelled C would be the center of the circle. The object is represented by the Arrow and as stated in the problem, it's half of the distance to the focal point from the mere now. To complete this ray diagram, we are going to need to plot out the path of each of the representative race. I like to start with the P ray because it has a very clear initial path, so the P ray or the parallel right will be represented on by Red, and it is going to go from the object in a line that is parallel to the axis, like so and then it's going to reflect back through the focal point and We are going to extend that reflecting Ray on the other side of the Mir so that we can determine where it intersects with the other rays and will label that one P ray. Now the next one we will do is the F ray or use green for that one, the effort you could almost think of as the opposite of the Pierret. It's going Teoh initially pass through the focal point and then reflect parallel to the axis, and I will show I would use a dotted line to show where it extends behind the object and then here to the mirror. And then it's going to reflect back any wine parallel and again. We're going to extend that parallel line on the other side here to find out where those to intercept and this is the effort. Now we could use the point at which of these two lines intersect to determine the location of the image. But we're going to plot the sea ray as well to check our work, so we'll use blue for that one. The sea ray, as its name suggests, is going to pass through the sea point with center of curvature and it's actually going to reflect back in the same a path that it takes initially. So again I will use a dotted line to show where it's extended behind the object, and then it's gonna go to the mere like that and remember, it's gonna extend back in the same, reflect back in the same path. But we need to extend it on the other side of the mirror to see where intersex. And so now we can see all three of these lines are intersecting at that same point will label that with Sea Ray, and now we can use that that point of intersection to determine the location of the image. So the image is going to extend up to that point, and we use an arrow for the images like we did the object. Only this time I'll use a dotted line so we know it's not the object itself, and we'll label that one image, and we can now use this completed diagram to answer the rest of the question. So we see that the image is, in fact, upright omits has the same orientation of the object. It's on the same side of the axis on. Then, when it comes to whether it is a real or virtual image, you can ask yourself this question. Is there any light passing through the image? In this case, the rays that are on the same side of the mirror with the image are just those extensions that we drew with the dotted lines, and therefore there is no light passing through the image, making this a virtual image.

View More Answers From This Book

Find Another Textbook

Numerade Educator

University of Washington

University of Winnipeg

In physics, wave optics is the study of the behavior of light, or other elec…

Interference is a phenomenon in which two waves superpose to form a resultan…

(a) Use a ray diagram to determine the approximate location of the image pro…

An object is a distance $f / 2$ from a convex lens. (a) Use a ray diagram to…

An object is a distance 2$f$ from a convex lens. (a) Use a ray diagram to fi…

Draw a ray diagram to locate the image of an object placed inside the focal …

(II) (a) Where should an object be placed in front of a concave mirror so th…

(II) (a) Where should an object be placed in front of aconcave mirror so…

An object is located midway between the focal point and the center of a conc…

A concave spherical mirror has a radius of curvature of magnitude $24.0 \mat…

A real object’s distance from a converging lens is five times the focal leng…

An object is located three times the focal length from a concave spherical m…

03:54

08:11

A person driving at 17 $\mathrm{m} / \mathrm{s}$ crosses the line connecting…

04:24

CE Predict/Explain A kitchen has twin side-by-side sinks. One sink is filled…

01:17

How much time does it take for the current in an $R L$ circuit with $R=130 \…

03:09

Predict/Calculate A long, straight wire carries a current of 14 A. Next to t…

04:09

A charge of 22.5$\mu \mathrm{C}$ is located at $(4.40 \mathrm{m}, 6.22 \math…

07:50

A coin is lying at the bottom of a pool of water that is 5.5 feet deep. View…

16:23

Predict/Calculate $A 15.0-V$ battery is connected to terminals A and B in Fi…

07:52

A 2.05 -cm-tall object is placed 30.0 $\mathrm{cm}$ to the left of a converg…

02:46

CE The plates of a parallel-plate capacitor have constant charges of $+Q$ an…

92% of Numerade students report better grades.

Try Numerade Free for 30 Days. You can cancel at any time.

Annual

0.00/mo 0.00/mo

Billed annually at 0.00/yr after free trial

Monthly

0.00/mo

Billed monthly at 0.00/mo after free trial

Earn better grades with our study tools:

Textbooks

Video lessons matched directly to the problems in your textbooks.

Ask a Question

Can't find a question? Ask our 30,000+ educators for help.

Courses

Watch full-length courses, covering key principles and concepts.

AI Tutor

Receive weekly guidance from the world’s first A.I. Tutor, Ace.

30 day free trial, then pay 0.00/month

30 day free trial, then pay 0.00/year

You can cancel anytime

OR PAY WITH

Your subscription has started!

The number 2 is also the smallest & first prime number (since every other even number is divisible by two).

If you write pi (to the first two decimal places of 3.14) backwards, in big, block letters it actually reads "PIE".

Receive weekly guidance from the world's first A.I. Tutor, Ace.

Mount Everest weighs an estimated 357 trillion pounds

Snapshot a problem with the Numerade app, and we'll give you the video solution.

A cheetah can run up to 76 miles per hour, and can go from 0 to 60 miles per hour in less than three seconds.

Back in a jiffy? You'd better be fast! A "jiffy" is an actual length of time, equal to about 1/100th of a second.