3) = e^{0.3}$. The Maclaurin series for a function $f(x)$ is given by $\sum_{k=0}^{\infty} \frac{f^{(k)}(0)x^k}{k!}$. For the function $f(x) = e^x$, we have $f^{(k)}(x) = e^x$ for all $k \geq 0$. Therefore, the Maclaurin series for $f(x) = e^x$ is
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