00:01
Part a of the question, the intensity is defined as the amount of energy received per unit area per unit time.
00:07
So, mathematically, the relation between intensity and area of the image is given by i equals to 1 by a1.
00:15
So, it is proportional.
00:18
Intensity is directly proportional to the area.
00:21
Okay? 1.
00:23
So here, a is the area of the image.
00:26
So let h .i is horizontal dimension of the image.
00:30
And hv is the vertical dimension of the image.
00:35
And assume q is the image distance and theta is the angle made by the light ray with the principal axis.
00:41
So we can write the angle theta equals to hv divided by q as area angle is not changing.
00:49
So we can write h horizontal dimension is directly proportional to q...