00:01
For this problem, we have to find the slope of the tangent line to f at point p.
00:06
Using the definition in the red box here, which is m sub a equals the limit as h approach to 0, of f of a plus h minus f of a all over h.
00:16
So the first thing i want to do is start building my equation for m sub a by substituting a plus h into the f of x equation for every where i see x, and then also plugging in for a.
00:32
So m sub a equals to the limit as h approaches 0 of a plus h cubed minus a cubed all over h.
00:52
So now i have to multiply the a plus h cubed and that's going to give me the limit as h approaches zero of a cube plus 3 a squared h plus 3 a squared plus h squared plus h cubed minus a cubed all over h so if you look at the numerator you'll see that a cube does cancel out with this a cube here leaving us with the limit as h approaches 0 of 3a squared h plus 3ah squared plus hq h h h q, h.
02:05
Now plug it in for zero, that's going to, i'm sorry, not plugging in for zero, but first we have, we see that each term has an h that the h in the denominator can cancel out with.
02:23
So this h here, one of the h is here, and one of the h is here, counsels out with this h here.
02:33
So now the equation becomes the limit.
02:37
This h approaches 0 of 3a squared plus 3ah plus h squared.
02:53
Now i can plug in for 0, and that gives me 3a squared because both of these cancel out due to the h being 0.
03:07
And that is my slope.
03:20
So the next part of this problem asks us to find an equation of the tangent line at the point p, which is at 2f2 for the equation f of x equals x cubed.
03:35
So the first thing i'm going to do is i'm going to find my y value for the point p by substituting in the 2 for x.
03:46
So f of 2 equals to 2 cubed, which equals to 8.
03:54
So my y value is 8...