00:01
For this problem on the topic of the schrodinger equation, we want to give you use the given amplitude to write down the total wave function for the ground state of a harmonic oscillator, and then use the momentum operator to find the expectation value of p squared.
00:17
So we can just write down the total wave function, epsilon of x and t, as for the ground state, psi, x, and t is a function of x and t, is equal, to using a knot that is provided m omega over h bar pi, all to the power 1 over 4, e to the minus m omega x squared, divided by 2 h bar times e to the minus i omega t over 2.
01:13
And for part b, we have the momentum operator, px or p to be h bar over i d by d x and so the expectation value of p squared is equal to the integral from minus infinity to infinity of the ps i star of x and t times h bar over i d by d x all squared times epsilon of x and t d x.
02:00
Now if we find the first derivative of psi not, we get dipsi not d x...