00:01
All right, so here's the problem 32 for chapter 19.
00:05
Part a, calculate the entropy change for vaporization of water at 25 and 100 degree.
00:13
So look up the numbers, we have delta h of vaporization of water at 25 degree equal to 44 .02 kilojoules per mole.
00:30
And the delta h of vaporization of water at 100 degrees is equal to 40 .67 kilojoules per mole.
00:44
So if we have the equation, delta s equal to q reversible, divided by temperature.
00:53
At 25 degree, we will have 44 .02 kilojoules per mole, divided by 25 plus 273 kelvin and we want to change this from kilojoules to jewels have 1 ,000 joules divided by 1 kilojoule and we get a number of 148 joules per more per kelvin so for the delta s of the 100 degree we will have 40 .67 kilojoules per mole divided by the temperature which is 100 plus 273 kelvin times thousand joules divided by one kjoules that is equal to a hundred oh nine joules per mole per kelvin all right so then we move to part two part b, and it's asking you from your knowledge of microstates and the structure of water, explain this difference of the two values.
02:24
So the two values we see here, the first one at 25 degree, is a larger number compared to the delta s of the 100 degree water.
02:36
So we know that water at 25 degree, there are significance of hydrogen bonds between the water...