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A Van de Graaff generator is charged so that a proton at its surface accclerates radially outward at $1.52 \times 10^{12} \mathrm{m} / \mathrm{s}^{2}$ . Find (a) the magnitude of the clectric force on the proton at that instant and (b) the magnitude and direction of the clectric field at the surface of the generator.

a. $2.54 \times 10^{-15} \mathrm{N}$

b. $1.59 \times 10^{4} \mathrm{N} / \mathrm{C}$

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Why there of the human problem? The magnitude off the electric force on a proper tone is given by the Newton's equation. There is a physical to end me. Ah must be here for a proper on this 1.67 times 10 to the power minus 27 kg Times exploration, which is 1.52 times 10 to the power Truls. This gives us the force off 2.5 for science, tended by the minus 15 Newton's. It won't be from here we can find electric field active feel equal force for unit charge. So, force, we just found this 2.54 times. Think about minus 15 divided by the charge. We have years 1.6 times Think about minus 19 Coolum. This gives us the electric field off 1.59 times 10 to the power four Newtons per cool through this desire were electric field