Question
A vertebra is subjected to a shearing force of 500 $\mathrm{N}$ . Find the shear deformation, taking the vertebra to be a cylinder 3.00 $\mathrm{cm}$ high and 4.00 $\mathrm{cm}$ in diameter.
Step 1
Step 1: The shear deformation $\Delta x$ is given by the formula: \[\Delta x = \frac{1}{G} \cdot \frac{F}{A} \cdot L\] where $G$ is the shear modulus, $F$ is the force, $A$ is the area, and $L$ is the original length. Show more…
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