Question
A vertical cylinder is divided into two parts by a frictionless piston in the ratio of $5: 4$. The piston is free to slide along the length of the vessel and length of the vessel is $90 \mathrm{~cm}$. Each of the two parts of the vessel contains $0.1$ mole of an ideal gas and the temperature of gas is $300 \mathrm{~K}$. The mass of the piston is:(a) $14 \mathrm{~kg}$(b) $12.7 \mathrm{~kg}$(c) $16 \mathrm{~kg}$(d) $15 \mathrm{~kg}$
Step 1
50 \, m\] \[L_2 = \frac{4}{5+4} \times 90 = 40 \, cm = 0.40 \, m\] Show more…
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