00:01
We're going to use a gaussian surface that is a cylinder.
00:04
So gaussian surface, we're going to have a cylinder with a radius r length of l.
00:19
And this is coaxial with the cylindrical charge distributions.
00:24
We know that the volume, volume of this gossian cylinder will be pi r squared times l.
00:37
And the area of its curved surface, so essentially the surface area, is equaling 2 pi r times l.
00:47
The charge on a length l of the charge distribution is going to be q.
00:54
This would equal the linear charge density multiplied by l, where the linear charge density is going to be equalling the density times pi r squared.
01:04
And so we can say that for part a, where r is less than r, we can say that then the enclosed charge would be equal to pi, or rather row pi r square times l.
01:20
And goss's law gives us that then the electric field times 2 pi r times the length will be equal to the charge enclosed divided by epsilon not...