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A very myopic man has a far point of 20.0 cm. What power contact lens (when on the eye) will correct his distant vision?

$-5.00 \mathrm{D}$

Physics 103

Chapter 26

Vision and Optical Instruments

Reflection and Refraction of Light

Wave Optics

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University of Michigan - Ann Arbor

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McMaster University

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Hey, guys, in this problem, we're told that a very myopic man has a Farpoint distance of 20 centimeters, the lens to retinal distance from his lines to the from his lens to his right. Nice two centimeters. And the taskings What power lines is needed to correct his vision? Very simple, straightforward plug and Shug problem. We're gonna use the formula. Power is equivalent to one over D I minus one over. D not won. Over the eye minus one plus one over D not right now. The power is what we're solving for r D. I, in this case is going to be our Farpoint are Farpoint is gonna be our d i and then our lens to write in the distance is gonna be okay. No, our Farpoint is actually gonna be our Theo and our lens to Ah, it's right that again are far ones, actually, um, beer d o. And our lens. To write in distance is gonna be our d I just to stay consistent with all their problems that I've been doing. So now we basically have three variables. We have one unknown. We know two of them. We just plug in and we just solved. So plugging in for that we get power is equal to one over 0.200 because of the fact that lets program Oh, no. 0.2 Sorry, I was looking at the wrong one. This is the lens to writing a distance the d ay that we just plugged in plus one over 0.200 And if we plug this into our calculator and solve this, we will get our we will get our power and our power is going to be 55.0 dy Oh, Peters. Now the thing is, this isn't this isn't the final answer. Now the power of the eye for a normal, distant vision is 50 Daio Peter's So that con attract So the contract lens or the lens that he should be going with should be 50 point of old eye openers minus 55 point Odai openers making his lens negative 5.0 eye openers. So just to recap what we did there we just found the power of his eye with the lens included. That's our 55 die. Oh, Peters and we subtracted the normal distant vision from we subtracted the normal. We subtracted the 55 die openers from the normal this division to get what the lens should be. This is a D, by the way, right here, toe our line should be negative five.

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