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Hey guys, in this problem, we are told that a very myopic man has a far point distance of 20 centimeters.
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The lens to retina distance from his lens to his retina is 2 centimeters.
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And it's asking us what power lens is needed to correct his vision.
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Very simple, straightforward plug -and -shug problem.
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We're going to use the formula of power is equivalent to 1 over d -i minus 1 over d -0.
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1 over d .i plus 1 over d .0.
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Right now, the power is what we are solving for.
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Our d .i in this case is going to be our far point.
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Our far point is going to be our d .i.
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And then our lens to retina distance is going to be o.
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No, our far point is actually going to be our d .o.
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And our lens to, let's write that again.
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Our far point is actually going to be our d .o.
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And our lens to retent distance is going to be our d .i...