00:01
Good evening everyone.
00:03
So today we're going to work through a problem where we've got two different objects.
00:06
We've got a scooter and we've got a car or an automobile.
00:10
In this case, both automobile and scooter battery produce a potential difference equal to this 12 volts here.
00:19
Now the scooter's battery, however, only produces a total charge of 4 ,000 kouloms or 4 kiloquons.
00:26
While the car obviously is going to have a much bigger charge, battery where it's located around 30 kilocaloms or 30 ,000 couloms.
00:36
The question then asks us to compute the energy that each of these batteries will output, given the potential difference of 12 volts.
00:46
Now, a really important equation that we're going to need for this problem is the energy e is equal to the potential difference delta v multiplied by the charge q.
01:00
So as you can see using this equation and our givens, we can simply simply we can simply plug our numbers in and compute the energy of the car and the energy of the scooter.
01:10
So starting with the energy of the scooter, let's go ahead and leverage this as e, subscript s for energy of scooter.
01:18
This is going to be equal to the potential difference of the scooter, which is 12 volts, multiplied by the charge of the scooter's battery, which is 4 kiloons...