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A voltage $\Delta V$ is applied to a series configuration of $n$ resistors, each of resistance $R$ . The circuit components are reconnected in a parallel configuration, and voltage $\Delta V$ is again applied. Show that the power consumed by the series configuration is 1$/ n^{2}$ times the power consumed by the parallel configuration.

\begin{array}{l}{\text { The power in series is } \frac{1}{n^{2}} \text { the power of the parallel configuration. This makes }} \\ {\text { reasonable sense as well. The more resistors in parallel, the more branches }} \\ {\text { there are and the more current can be drawn. }}\end{array}

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