## \begin{array}{l}{\text { The power in series is } \frac{1}{n^{2}} \text { the power of the parallel configuration. This makes }} \\ {\text { reasonable sense as well. The more resistors in parallel, the more branches }} \\ {\text { there are and the more current can be drawn. }}\end{array}

### Discussion

You must be signed in to discuss.
##### Christina K.

Rutgers, The State University of New Jersey

##### Andy C.

University of Michigan - Ann Arbor

### Video Transcript

in this problem, we are asked to show that the part in Serie Z is equals two whenever n squared off the body that is PC musicals to one hour and square off key people. In order to derive this relation, let me kill Clodagh. Equal into resistance for serious combination are equal in series equals two. You know, Uh, so the bar for cities combination can be right PC really close to Don't tell the old square You worried by Ari Serious Now setting the value off decided Siri's into this question. From here we can, right soapy series equals two Delta v Old Square you wanted by Anna. That's cool. It equation one No, like we learned resistance for But the combination can be the Internet. Ari parent equals two. Are you wanted by N? No. The party in battle combination can be Internet repairable equals two. That'll be squared, divided by our department sitting the value of this sorry pattern into the square. And we would get people really close to and in two days a week old squared, divided by our they're schooled equation too. No dividing equating one By equating to we will get Siri's rewarded by pre parliament calls to wonder what it by and square or it can be Internet. You see reason goes to when you wanted by and square into people, so when's proved?

Other Schools
##### Christina K.

Rutgers, The State University of New Jersey

##### Andy C.

University of Michigan - Ann Arbor