Question
A voltmeter has a resistance $G$ and range $V .$ Calculate the resistance to be used in series with it to extend its range to $n V$.
Step 1
The maximum current for full scale deflection, denoted by $I_G$, is given by Ohm's law as $I_G = \frac{V}{G}$. Show more…
Show all steps
Your feedback will help us improve your experience
Vishal Gupta and 78 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A voltmeter has a resistance of $G$ ohm and range $V$ volt. The value of resistance used in series to convert it into voltmeter of range $n V$ volt is a. $n G$ $\mathbf{b}(n-1) G$ c. $G / n$ d $G /(n-1)$
A voltmeter has resistance of 2000 ohms and it can measure upto 2V. If we want to increase its range to 10 V, then the required resistance in series will be?
The range of a galvanometer of resistance $\mathrm{G}$ ohm is $\mathrm{V}$ volt. The resistance required to be connected in series with it in order to convert it into voltmeter of range $\mathrm{nV}$ volt will be (A) (G/n) (B) $\mathrm{nG}$ (C) $(\mathrm{n}-1) \mathrm{G}$ (D) $[\mathrm{G} /(\mathrm{n}-1)]$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD