Since the rim is a thin circular hoop, we can use the formula for the moment of inertia of a hoop: $I_\text{rim} = MR^2$, where $M$ is the mass of the rim and $R$ is the radius of the wheel.
$I_\text{rim} = (1.40\,\text{kg})(0.300\,\text{m})^2 =
Show more…