Question
A water pump lifts water from a level $10 \mathrm{~m}$ below the ground. Water is pumped at a rate of $30 \mathrm{~kg} /$ minute with negligible velocity. Calculate the minimum horsepower the engine should have to do this.
Step 1
This is done by dividing the given rate by 60 (since there are 60 seconds in a minute). So, we have: \[ m/T = 30 \, \text{kg/min} \, / \, 60 = 0.5 \, \text{kg/sec} \] Show more…
Show all steps
Your feedback will help us improve your experience
Aja S and 64 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
At what rate can a half-horsepower well pump deliver water to a tank $60 \mathrm{m}$ above the water level in the well? Give your answer in $\mathrm{kg} / \mathrm{s}$ and gal/min.
At what rate can a half-horsepower well pump deliver water to a tank $50 \mathrm{~m}$ above the water level in the well? Give your answer in $\mathrm{kg} / \mathrm{s}$ and $\mathrm{gal} / \mathrm{min}$.
A pump lifts $200 \mathrm{~kg}$ of water per hour a height of $5.0 \mathrm{~m} .$ What is the minimum necessary power output rating of the water pump in watts and horsepower?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD