00:01
So we should first write the equation that describes these waves, these waves.
00:05
And this is going to be y of xt.
00:08
It's going to be 0 .0275 meters.
00:14
This is 2 .75 centimeters.
00:16
However, i just wanted to convert into meters immediately.
00:20
So we'll have cosine, and then it'll be times cosine.
00:24
And then this will be 0 .410 radians per centimeter.
00:30
Times x and then plus 6 .20 radiance per second times t.
00:41
So this will be our equation for the wave.
00:44
And then we know that a standard equation for a wave is going to look like this.
00:52
A cosine of k x minus omega t.
00:58
And then we are asked, the question is asking us, how long will it take for a waveform essentially for a complete waveform to pass by the fishermen? and the time to complete one wave pattern is called the period.
01:15
So we can say that omega is going to be equal to 2 pi over t, where t is the period.
01:22
T is going to be the time for one complete wave pattern to pass the fisherman.
01:27
We simply need to solve for t.
01:31
And this is going to be 2 pi divided by 6 .2 radiance per second.
01:37
We found the omega here by relating this equation to this equation.
01:45
And the coefficient of the t is going to line up with the omega or the angular frequency of this wave.
01:52
So the angular frequency of the wave is found simply by taking it from the original equation.
01:58
And this is going to be equal to 1 .013 seconds.
02:04
Now, they're asking us to find the horizontal distance covered so we can use the wave number.
02:12
This is going to be 2 pi over lambda.
02:15
And the horizontal distance covered in one complete wave pattern would be considered the wavelength of the wave.
02:22
So it's convenient that we can just use the equation for the wave number, isolate the wavelength, we can plug in for our constants.
02:32
K, we're gunning it from the equation.
02:35
It's going to be this variable right here.
02:37
So 0 .410 radians per centimeter.
02:42
And then of course the wavelength is going to be 15 .325 centimeters.
02:50
Or we can say the wavelength is equal to 0 .15325 meters.
03:01
And then at this point, we can find the frequency.
03:05
So part b is asking us to find the frequency...