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A wave traveling on a Slinky\otimes that is stretched to 4 $\mathrm{m}$ takes 2.4 $\mathrm{s}$ to travel the length of the Slinky and back again. (a) What is the speed of the wave? (b) Using the same Slinky stretched to the same length, a standing wave is created which consists of three antinodes and four nodes. At what frequency must the Slinky be oscillating?

a) $v=3.33 \mathrm{m} / \mathrm{s}$b) $f=1.25 \mathrm{Hz}$

Physics 101 Mechanics

Physics 103

Chapter 16

Oscillatory Motion and Waves

Periodic Motion

Wave Optics

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

McMaster University

Lectures

02:51

In physics, wave optics is…

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Interference is a phenomen…

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as we know velocity off a wave is given by wavelength times frequency on dhe distance traveled about it by time as the as it is mentioned in the question that it takes, uh, it takes way to travel back and forth with 2.4 seconds. So back and forth means eight meters on dhe, divided by two on four, will be equal to 3.33 meters per seconds. So that's the velocity off a wave. And in second part, question says that spring is or the slinky is stretched to the same length, so the velocity is same. Velocity is not changing. Now. It is given to us that they are three anti notes on full notes. So let's say one. So this makes 1 1902 notes chill and three so three anti notes. The diagram is not to the symmetry, but as you can see, we have full notes. One, two, three and four and three anti notes. One way was finished between three notes. Oh, it has to anti notes. So we have half away of extra what? In this case, it means that we have see half wave in this configuration so lend is equal to 3/2 0 waving. So this is the full wavelength. One lander, just half lambda, makes length. So now we can use frequencies equal to velocity divided by wailing, which is equal to 3.33 divided by 2/3 off the length, which is four meters said This comes from here, so this will be equal to 1.25 hoods.

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