Question

A weather balloon filled with He gas has a volume of $2.00 \times 10^{3} \mathrm{m}^{3}$ at ground level, where the atmospheric pressure is 1.000 atm and the temperature $27^{\circ}$ C. After the balloon rises high above Earth to a point where the atmospheric pressure is 0.340 atm, its volume increases to $5.00 \times 10^{3} \mathrm{m}^{3} .$ What is the temperature of the atmosphere at this altitude?

Name: Problem 15, Chapter 6: General Chemistry: Principles and Modern Applications
Uploaded: 2020-06-22T01:40:10-08:00
Duration: 1 min 3 s
Channel: David Collins
Description: A weather balloon filled with He gas has a volume of 2.00 ×10^3 m^3 at ground level, where the atmospheric pressure is 1.000 atm and the temperature 27^∘ C. After the balloon rises high above Earth to a point where the atmospheric pressure is 0.340 atm, its volume increases to 5.00 ×10^3 m^3 . What is the temperature of the atmosphere at this altitude?

   A weather balloon filled with He gas has a volume of $2.00 \times 10^{3} \mathrm{m}^{3}$ at ground level, where the atmospheric pressure is 1.000 atm and the temperature $27^{\circ}$ C. After the balloon rises high above Earth to a point where the atmospheric pressure is 0.340 atm, its volume increases to $5.00 \times 10^{3} \mathrm{m}^{3} .$ What is the temperature of the atmosphere at this altitude?

General Chemistry: Principles and Modern Applications

Ralph H. Petrucci,… 11th Edition

Chapter 6, Problem 15

Instant Answer

Solved by Expert David Collins

06/22/2020

Step 1

This can be written as: \[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \] Show more…

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A weather balloon filled with He gas has a volume of $2.00 \times 10^{3} \mathrm{m}^{3}$ at ground level, where the atmospheric pressure is 1.000 atm and the temperature $27^{\circ}$ C. After the balloon rises high above Earth to a point where the atmospheric pressure is 0.340 atm, its volume increases to $5.00 \times 10^{3} \mathrm{m}^{3} .$ What is the temperature of the atmosphere at this altitude?

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Key Concepts

Ideal Gas Law

This fundamental law, expressed as PV = nRT, relates the pressure, volume, temperature, and amount of a gas. It is essential for analyzing how changes in one state variable (such as pressure or volume) affect another when the number of moles remains constant.

Combined Gas Law

The combined gas law, derived under the assumption of a constant number of moles, relates two different states of a gas using the formula (P1V1)/T1 = (P2V2)/T2. This law is crucial for solving problems where a gas experiences simultaneous changes in pressure, volume, and temperature.

Temperature Conversion to Kelvin

Temperature must be measured in an absolute scale (Kelvin) when using gas laws. Converting from Celsius to Kelvin is essential because gas law equations require an absolute temperature to ensure accurate calculations and proportional relationships.

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