00:01
Okay, we have a dot on a screen which follows this position equation as a function of time.
00:08
So we see in the ihat direction it follows this, so 4 .4 plus 2 .8 times t squared.
00:17
And then the y direction, it follows this 5 .5 times t.
00:23
And what we want to find out is the average velocity.
00:30
During from t equals 0 to 2 seconds.
00:33
So we know that average velocity looks like this.
00:40
So for the x component of our velocity, it's going to be the change in position, divided by the change in time.
00:47
And then vy, of course, it's going to be the same thing.
00:50
It's not a vector.
00:51
It's average y velocity, the change in y position, change in time.
00:58
And so what we need is the initial position and final position.
01:03
So the initial position, we get just by plugging t equals 0 in.
01:10
So that's going to be 4 .4 centimeters in the i -hatt direction, an x direction.
01:19
And then the final we get for plugging in t -cels 2.
01:24
So for that, we get 15 .6 centimeters, and then 11 centimeters in the y direction.
01:35
All right.
01:36
And now we have these so we could calculate, what are we.
01:38
Our average velocities are.
01:40
So average vx velocity is going to be our final position, 15 .6 centimeters minus 4 .4 centimeters, divided by the change of time, which is 2.
01:57
And what we get from this is 5 .6 centimeters per second.
02:05
And then vy is quite similar, which is going to be 11 over 2.
02:11
Or 5 .5 centimeters per second.
02:15
So this is the average velocity and since we wrote it component -wise, this is the vector of average velocity, which we know both contains magnitude and direction.
02:28
Okay, so let's move on to part b.
02:34
So for part b, we want to know the instantaneous velocity...