00:01
Okay, so we are given this molecule structure c, 3, c, h, c, h, c, h, c, h, c, h, c2, ch2, ch2, ch3, right? let's call this a and this is b.
00:32
This is like this.
00:53
Okay, so first part is the starting alkyme.
01:06
So to write that this is going to be something like this.
01:13
Okay, we can just look at the structure above and make the starting structure like this.
01:34
Okay, so this is trans three heptin.
01:42
Okay, because there are seven carbon atoms.
01:49
And this is for a part.
01:52
For b part, we can also draw the same structure.
01:55
Just by looking at it.
02:00
H is going to be here.
02:02
This is ch2, ch2, ch3.
02:07
This is again h, ch2, ch3.
02:14
So this is cis 3 heptime.
02:20
Okay? next, this is the starting structure.
02:27
The next question, they are asking for other products that can be formed.
02:32
So since addition of a peroxy acid to an alkene is a sin addition, oxygen can be added from above as well as below the plane.
03:25
Okay so let's just start by drawing the first structure um so you have two carbons instead of drawing the oxygen as shown in the question we draw it below and then we just have the same groups attached to it okay this is also the same thing and another thing is this is going to be a trans enchantumar you will also have a mirror image so how do you draw this mirror image just like sorry this is going to be carbon carbon oxygen h exactly how you draw enchantumers and how you write or draw mirror images for the structures you draw it this is going to be like this right and this is going to be like this if you look here hydrogen like this right so this is a mirror image moving on to the next one we will draw the structures now so the first one would be a chance in anshamar where oxygen is below the plane of carbon so we would have something like this ch2, ch2, ch3, this would be hydrogen, ch2, ch3, right? and this is the cis enchantumar.
06:08
Now i will draw the mirror image of the product...