Question
(a) What force is required to stop a $1250-\mathrm{kg}$ car traveling $95.0 \mathrm{~km} / \mathrm{h}$ within $4.00 \mathrm{~s} ?$ (b) How far does the car travel during its deceleration?
Step 1
We do this by dividing the given speed by 3.6. So, the initial speed $v_i$ is $95.0 \, \mathrm{km/h} \div 3.6 = 26.389 \, \mathrm{m/s}$. Show more…
Show all steps
Your feedback will help us improve your experience
Shahab Ullah and 82 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
(a) What force is required to stop a $1250-\mathrm{kg}$ car traveling $95.0 \mathrm{~km} / \mathrm{h}$ within $4.00 \mathrm{~s}$ ? (b) How far does the car travel during its deceleration?
(a) What force is required to slow a 1350-kg car traveling 90.0 km/h to 25.0 km/h within 4.00 s? (b) How far does the car travel during its deceleration? (c) How long does it take for the car to come to a complete stop at this same rate of deceleration?
(a) What force is required to slow a $1350-\mathrm{kg}$ car traveling $90.0 \mathrm{~km} / \mathrm{h}$ to $25.0 \mathrm{~km} / \mathrm{h}$ within $4.00 \mathrm{~s} ?$ (b) How far does the car travel during its deceleration? (c) How long does it take for the car to come to a complete stop at this same rate of deceleration?
Momentum
Momentum and Impulse
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD