Question
(a) What is the average kinetic energy in joules of hydrogen atoms on the 5500ºC surface of the Sun? (b) What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is $6.00 \times 10^{5} \mathrm{K} ?$
Step 1
The formula to convert Celsius to Kelvin is K = C + 273.15. So, for a temperature of 5500ºC, the equivalent in Kelvin is 5500 + 273.15 = 5773.15 K. Show more…
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What is the average kinetic energy in joules of hydrogen atoms on the $5500^{\circ} \mathrm{C}$ surface of the Sun? (b) What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is $6.00 \times 10^{5} \mathrm{K} ?$
(a) What is the average kinetic energy (in J) of hydrogen atoms on the 5500°C surface of the sun? (b) What is the average kinetic energy (in J) of helium atoms in a region of the solar corona where the temperature is 5.80 x 10^5 K?
(a) What is the average kinetic energy in joules of a hydrogen atom on the 5500°C surface of the Sun? The Boltzmann's constant is k = 1.38x10^-23 J/K. KEav: (b) What is the average kinetic energy of a helium atom in a region of the solar corona where the temperature is 6x10^5 K? KEav:
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